RE: Section 4.1 clarifications

["Julian Satran" <Julian_Satran@il.ibm.com>]

I am not sure that a loop is complex code but we could limit ourselves to 128 bit integers to cover at least some addresses.

Julo

"Michael Krueger" <michael.krueger@windriver.com> 04/26/2002 12:41 AM Please respond to "Michael Krueger"

To:        "THALER,PAT (A-Roseville,ex1)" <pat_thaler@agilent.com>, "Julian Satran" <Julian_Satran@il.ibm.com>         cc:        <ips@ece.cmu.edu>, "iSCSI Team" <iscsiteam@windriver.com>         Subject:        RE: Section 4.1 clarifications

Pat,

> I think Michael's point is that the decimal encoding for a 1024
> byte binary is around 2500 characters (if I've done the math
> right) while the hexadecimal encoding is 2050 characters and
> someone anticipating the binary might not have made wherever they
> store the string before conversion big enough for the extra ~450
> characters.
>
> The extra storage is small compared to the amount of data one may
> be moving later once the connection is up, but I also don't see
> the readability argument as applying to these large constants.

Actually, I'm concerned neither with storage space nor with speed, but
rather with code complexity.  Unlike hexadecimal and base-64 encoding, there
is not a simple correspondence between decimal digits in the string
representation and bit locations in the binary item.  Most implementation of
decimal-to-binary conversion functions like strtoul() do integer arithmetic
to obtain the binary representation, but this isn't feasible for binary
items larger than 4 (or, at an absolute maximum, 8) bytes.  Show me a simple
algorithm or a widely available library function for converting a
2,467-digit string to its 1024-byte binary representation, and I'll use it;
otherwise, support for decimal encoding of large binary items seems like a
needless complication that pays back very little added value.

Michael

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Michael J. Krueger              mailto:michael.krueger@windriver.com
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